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<P class=MsoNormal style="MARGIN: 0in 0in 0pt"><FONT face="Times New Roman"
size=3>Hello looking for help. I must be stupid.</FONT></P>
<P class=MsoNormal style="MARGIN: 0in 0in 0pt"><FONT size=3><FONT
face="Times New Roman"> <o:p></o:p></FONT></FONT></P>
<P class=MsoNormal style="MARGIN: 0in 0in 0pt"><FONT face="Times New Roman"
size=3>I wrote a geotiff parser just to know how! The test file uses
little-endian “MM”. The offsets points to correct information for tags with
Field Types other than the two double (8 byte) values; tags 33550 & 33922.
<SPAN style="mso-spacerun: yes"> </SPAN>ModelPixelScaleX is suppose to = 60
and Y = 60. Raw directory Data = 33550, 12, 3, 262830; The 262830 offset points
to (8bytes) 0,0,0,0,0,0,78,64 and Y = the same 78,64 value. There is no way
using little or big-endian that this will ever = 60! Using little-endian actual
value would be 4.6********+e18. A Huge # and the same results with
ModelTiePointTagI-K = huge #’s! </FONT></P>
<P class=MsoNormal style="MARGIN: 0in 0in 0pt"><FONT face="Times New Roman"
size=3>The file is OK as other readers extract the correct values. IS THERE SOME
MATH REQUIRED to convert 4.6*****+e18 # to 60?</FONT></P>
<P class=MsoNormal style="MARGIN: 0in 0in 0pt"><FONT size=3><FONT
face="Times New Roman"> <o:p></o:p></FONT></FONT></P>
<P class=MsoNormal style="MARGIN: 0in 0in 0pt"><FONT face="Times New Roman"
size=3>Thanks for any insight; no one else seems to know.</FONT></P><SPAN
style="FONT-SIZE: 12pt; FONT-FAMILY: 'Times New Roman'; mso-fareast-font-family: 'Times New Roman'; mso-ansi-language: EN-US; mso-fareast-language: EN-US; mso-bidi-language: AR-SA">John
Rountree</SPAN></DIV></BODY></HTML>