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<div class="moz-cite-prefix">Paul,<br>
<br>
Doing the math on your TIFF air photo, I get:<br>
<br>
40 sq mi X (63360 inches per mi / 6 inches per pixel )**2 =
4,460,5440,000 pixels<br>
and so:<br>
4,460,5440,000 pixels X 3 bytes per pixel = 12.46 Gbytes<br>
<br>
So 800 sq mi would be 250 Gbytes<br>
<br>
After tiling, I expect it would be 250 to 500 Gbytes. You could
try gdal2tiles.py on a subset of the air photo mosaic to get a
better idea...<br>
<pre class="moz-signature" cols="72">Best Regards,
Brent Fraser</pre>
On 1/29/2013 10:27 AM, Paul Wickman wrote:<br>
</div>
<blockquote
cite="mid:CAFo+T1m7cT_c0fquDFMGAu0wCNZ+qLgGAWSMtG5THKEpoqkROA@mail.gmail.com"
type="cite">
<div dir="ltr">Yes, bytes. Zowie... I have a TIFF of an air
photo for one of our other municipalities (also 6-inch
resolution), which is 20 GB (uncompress). That coverage is only
~40 square miles. So, for a single ~800 square mile county also
at 6-inch resolution I'd potentially be looking at 400 GB for
the uncompressed source or... somewhere on the order of ~800 GB
tiled? Does that sound right?
<div>
<br>
</div>
<div style="">Anybody from MnGeo on this list with any input?</div>
</div>
<div class="gmail_extra"><br>
<br>
<div class="gmail_quote">On Tue, Jan 29, 2013 at 11:15 AM, Brent
Fraser <span dir="ltr"><<a moz-do-not-send="true"
href="mailto:bfraser@geoanalytic.com" target="_blank">bfraser@geoanalytic.com</a>></span>
wrote:<br>
<blockquote class="gmail_quote" style="margin:0 0 0
.8ex;border-left:1px #ccc solid;padding-left:1ex">
<div text="#000000" bgcolor="#FFFFFF">
<div>Do you mean how many bytes?<br>
<br>
Looking at my Landsat tile pyramids (levels 4 to 12),
they're about the same number of bytes (hmm, I expected
them to be double...)<br>
<br>
But my source images:<br>
- no compression on existing files (tiffs, e.g not
jpeg)<br>
- 3 band (color) imagery<br>
<br>
The resulting tiles:<br>
- compressed PNGs<br>
- four bands (one alpha channel for transparency)<br>
<br>
So my guess is somewhere between "same size" to "double
the number of bytes" (unless the source imagery is
compressed, then it will be 5 to 10 times larger)<br>
<br>
<pre cols="72">Best Regards,
Brent Fraser</pre>
<div>
<div class="h5"> On 1/28/2013 5:53 PM, Paul Wickman
wrote:<br>
</div>
</div>
</div>
<blockquote type="cite">
<div>
<div class="h5">
<div dir="ltr">Greetings,
<div><br>
</div>
<div>I know this type of question goes around
often in various flavors. Difficult to estimate
exact size of rendered tiles, but thought I'd
try to get some opinions.</div>
<div><br>
</div>
<div>
<div>I see this questions asked in a variety of
ways and I know it's not exactly precise on
how to get the answer, but I'll throw my
question out to see what I get ;)</div>
<div><br>
</div>
<div>We have a client who would like us to tile
and serve up high-resolution aerial
photography that they own. The area is about
800 square miles and the imagery is 6-inch
resolution. They'd like to be able to view the
imagery at zoom levels 11 through 20 (with
level 20 being 1 pixel=6 inches). Is there any
way at all to determine how large a resulting
raster tile set might be?</div>
<div><br>
</div>
<div>Many thanks,</div>
<div> Paul</div>
<div>
<div><br>
</div>
-- <br>
Paul Wickman<br>
CTO | Flat Rock Geographics<br>
<a moz-do-not-send="true"
href="tel:612.280.5850" value="+16122805850"
target="_blank">612.280.5850</a> | <a
moz-do-not-send="true"
href="mailto:paul@flatrockgeo.com"
target="_blank">paul@flatrockgeo.com</a><br>
<a moz-do-not-send="true"
href="http://www.flatrockgeo.com"
target="_blank">www.flatrockgeo.com</a> | <a
moz-do-not-send="true"
href="http://twitter.com/flatrockgeo"
target="_blank">twitter.com/flatrockgeo</a>
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</blockquote>
<br>
</div>
</blockquote>
</div>
<br>
<br clear="all">
<div><br>
</div>
-- <br>
Paul Wickman<br>
CTO | Flat Rock Geographics<br>
612.280.5850 | <a moz-do-not-send="true"
href="mailto:paul@flatrockgeo.com" target="_blank">paul@flatrockgeo.com</a><br>
<a moz-do-not-send="true" href="http://www.flatrockgeo.com"
target="_blank">www.flatrockgeo.com</a> | <a
moz-do-not-send="true" href="http://twitter.com/flatrockgeo"
target="_blank">twitter.com/flatrockgeo</a>
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