[GRASS-dev] Re: [GRASS-user] Get current location projection in a Python Script

[Glynn Clements]

Nikos Alexandris wrote:

> > > >>     # faster/ easier way: use of the "grass.region()" function
> > > >>     rows = int(grass.region()['rows'])
> > > >>     cols = int(grass.region()['cols'])
> > > > 
> > > > In 7.0, these fields are already integers; r40555 should be
> > > > backported.
> > > 
> > > AFAIK it has been backported some time ago.
> > > 
> > > http://trac.osgeo.org/grass/browser/grass/branches/releasebranch_6_4/lib/
> > > python/core.py#L503
> > 
> > Okay; change that to "I should 'svn update' the other branches more
> > often", then ;)
> 
> This means it should be like:
> 
> rows = grass.region()['rows']
> cols = grass.region()['cols']
> 
> Right?

Right; although you should store the result of grass.region() to avoid
redundant g.region commands, i.e.:

	rgn = grass.region()
	rows = rgn['rows']
	cols = rgn['cols']

-- 
Glynn Clements <glynn at gclements.plus.com>