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Yes, just call the "UpdateFeatures" method on an "MgResourceService"
instance.<br>
<pre class="moz-signature" cols="72">Regards, Kenneth Skovhede, GEOGRAF A/S
</pre>
<br>
<br>
Ivan Milicevic skrev:
<blockquote cite="mid:9CAB6B340CCF9E44BE4ACFCF56E67B07356B0A@supranet"
type="cite">
<pre wrap="">Kenneth, is it possible to edit dana in these tables?
-----Original Message-----
From: <a class="moz-txt-link-abbreviated" href="mailto:mapguide-users-bounces@lists.osgeo.org">mapguide-users-bounces@lists.osgeo.org</a>
[<a class="moz-txt-link-freetext" href="mailto:mapguide-users-bounces@lists.osgeo.org">mailto:mapguide-users-bounces@lists.osgeo.org</a>] On Behalf Of Kenneth
Skovhede, GEOGRAF A/S
Sent: Thursday, February 05, 2009 2:14 PM
To: MapGuide Users Mail List
Subject: Re: [mapguide-users] Programmatically add a layer from SDF
After creating the SDF FeatureSource, you can use MapGuide to query it:
<a class="moz-txt-link-freetext" href="http://mapguide.osgeo.net/files/mapguide/docs/webapi/d5/d10/class_mg_fea">http://mapguide.osgeo.net/files/mapguide/docs/webapi/d5/d10/class_mg_fea</a>
ture_service_7ca27aeb7ab769babccefd67d1335c34.html#7ca27aeb7ab769babccef
d67d1335c34
The results of DescribeSchema() gives you all the schemas/classes
supported by the SDF (yes, it may have many tables).
The MgClass item has a method called GetProperties() which will return
all the avalible columns
in the SDF file, including their type.
Regards, Kenneth Skovhede, GEOGRAF A/S
sekko970 skrev:
</pre>
<blockquote type="cite">
<pre wrap="">I need to add a new layer to my map with an SDF resource and using an
</pre>
</blockquote>
<pre wrap=""><!---->XML
</pre>
<blockquote type="cite">
<pre wrap="">template layer definition, but I don't know how to extract the name of
Feature Class and Geometry.
I'm using .NET WebAPI.
Could you help me?
Thanks in advance,
Fabio
</pre>
</blockquote>
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</pre>
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