[OpenLayers-Users] How to access style properties of features?

[Andreas Hocevar]

Hi,

Peter.Sykora at ooe.gv.at wrote:
> The following code creates a Vector layer using a styleMap where I set 
> the style properties within some functions:
>  
>
>     style = new OpenLayers.Style(template, {context: context});
>     styleMap = new OpenLayers.StyleMap({'default': style, 'select': 
> {fillOpacity: 0.7}});
>    
> ...
>     ergebnisL = new OpenLayers.Layer.Vector('Suchergebnis', {
>      styleMap: styleMap
>     });
>  
> I´d like to calculate the graphicXOffset manually within the function 
> getXOffset. Therefore I would need to access some style properties 
> like graphicWidth of my current feature. I thought that it should work 
> using something like gW=feature.Vector.style.graphicWidth but 
> feature.Vector is empty ...

Try feature.style.graphicWidth instead of feature.Vector.style.graphicWidth.

Regards,
Andreas.


-- 
Andreas Hocevar
OpenGeo - http://opengeo.org/
Expert service straight from the developers.