<html><head></head><body style="word-wrap: break-word; -webkit-nbsp-mode: space; -webkit-line-break: after-white-space; "><div>I should have proofread the email BEFORE I sent it.</div><div><br></div>Actually, it would be something like this:<div><br><div>var latlon = new OpenLayers.LonLat(tweet.geo.coordinates[0],tweet.geo.coordinates[1]);</div><div>latlon.transform(new OpenLayers.Projection("EPSG:4326"),map.getProjectionObject());</div><div>tweet.point = latlon;</div><div><br></div><div>This assumes that tweet.geo.coordinates[0],tweet.geo.coordinates[1] is something that the LonLat constructor will take.</div><div><br><div><div>On Jun 21, 2011, at 10:39 AM, B. Heath Robinson wrote:</div><br class="Apple-interchange-newline"><blockquote type="cite"><div style="word-wrap: break-word; -webkit-nbsp-mode: space; -webkit-line-break: after-white-space; "><div>Transform operates on the coordinates, it does not return a new coordinates. You should use it like this:</div><div>var latlon = weet.geo.coordinates[0],tweet.geo.coordinates[1];</div><div>latlon.transform(new OpenLayers.Projection("EPSG:4326"),map.getProjectionObject());</div></div></blockquote><blockquote type="cite"><div style="word-wrap: break-word; -webkit-nbsp-mode: space; -webkit-line-break: after-white-space; "><div>tweet.point = latlon;</div><div><br></div><br><div><div>On Jun 21, 2011, at 10:21 AM, Nicholas Efremov-Kendall wrote:</div><br class="Apple-interchange-newline"><blockquote type="cite">Hi guys thanks for the previous advice,<div><br></div><div>I'm still running into an issue, and I'm not sure how to resolve it. When I first use a OpenLayers.LonLat and transform the point, I get the lon converted correctect, but the lat is returned NaN. If I don't transform it, the coordinates remain correct.</div>
<div><br></div><div><div>tweet.point = new OpenLayers.LonLat(tweet.geo.coordinates[0],tweet.geo.coordinates[1]).transform(new OpenLayers.Projection("EPSG:4326"),map.getProjectionObject());</div><div><br></div><div>
I've been playing around with some different iterations, and I can get tweet.point to alert out with ever tweet that's pulled into the plotting function, but the markers aren't added. The issue seems to be with how I'm calling the transform function, because somehow after calling the function I get NaN's for the lat-lon's inside the point object. I'm really hitting a wall here.</div>
<div><br></div><div><div><br></div></div><div><br></div><div><div class="gmail_quote">On Tue, Jun 21, 2011 at 3:23 AM, Nick Kendall <span dir="ltr"><<a href="mailto:n.e.kendall@gmail.com" target="_blank">n.e.kendall@gmail.com</a>></span> wrote:<br>
<blockquote class="gmail_quote" style="margin:0 0 0 .8ex;border-left:1px #ccc solid;padding-left:1ex">
<div bgcolor="#FFFFFF"><div>Thanks! Will take another crack at this Tom! <br><br>Sent from my mobile device</div><div><div></div><div><div><br>On Jun 21, 2011, at 2:37 AM, "Sveen Atle Frenvik (Geomatikk IKT)" <<a href="mailto:Atle.Frenvik.Sveen@geomatikk.no" target="_blank">Atle.Frenvik.Sveen@geomatikk.no</a>> wrote:<br>
<br></div><div></div><blockquote type="cite"><div>
try using an OpenLayers.Geometry.Point instead of an
OpenLayers.LonLat<br>
<br>
ie (untested, but i think this is rather correct):<br>
<br>
<div>function parseTweetsQ(){</div>
<div> if (tweetsQ.length > 0) {</div>
<div> var tweet = tweetsQ.pop();</div>
<div> if (tweet.geo){</div>
<div> tweet.point = new OpenLayers.Geometry.Point(tweet.geo.coordinates[0],tweet.geo.coordinates[1]).transform(new
OpenLayers.Projection("EPSG:4326"),map.getProjectionObject());<br>
tweet.attributes = {}; //in this you coukd stuff
attributes of the tweet for easy access on clicks etc.<br>
</div>
<div> plotTwt(tweet);</div>
<div> }<br>
}<br>
}</div>
<div><br>
</div>
<div>
<div>function plotTwt(tweet){<br>
//why do you keep adding the layer for each tweet? <br>
</div>
<div> map.addLayer(tweetz);</div>
<div> tweet.marker = new OpenLayers.Feature.Vector(tweet.point,{attributes:{tweet.attributes]});</div>
<div> tweetz.addFeatures([tweet.marker]);<br>
}<br>
<br>
</div>
</div>
<br>
<br>
On 2011-06-21 05:00, Nicholas Efremov-Kendall wrote:
<blockquote type="cite">Hi Phil et al,
<div><br>
</div>
<div>Thanks for your response. The code as is does iterate through
the features as they are returned. I have a handle on it up to
the plotting function. An alert on the tweet.marker object
returns [object Object], while tweet.latlng returns readable
coordinates lon=38.6834,lat=-90.4313. I guess what I'm unsure
about is how to parse the object which is passed to the third
function. Thanks again.</div>
<div><br>
</div>
<div>
<div><br>
</div>
<div>function acquireTweets(){</div>
<div>$.getJSON(createTWTsrcURL(), function(data){</div>
<div>if(data.results)</div>
<div>$.each(data.results, function(i, tweet){</div>
<div>if (tweet.geo || tweet.location)</div>
<div>tweetsQ.push(tweet);</div>
<div>});</div>
<div>refreshQuery = data.refresh_url;</div>
<div>});}</div>
<div><br>
</div>
<div>function parseTweetsQ(){</div>
<div>if (tweetsQ.length > 0) {</div>
<div>var tweet = tweetsQ.pop();</div>
<div>if (tweet.geo){</div>
<div>tweet.latlng = new
OpenLayers.LonLat(tweet.geo.coordinates[0],tweet.geo.coordinates[1]);</div>
<div>plotTwt(tweet);</div>
<div>}}}</div>
<div><br>
</div>
<div>
<div>function plotTwt(tweet){</div>
<div>
map.addLayer(tweetz);</div>
<div>tweet.marker = new OpenLayers.Feature.Vector(new
OpenLayers.Geometry.Point(tweet.latlng).transform(new
OpenLayers.Projection("EPSG:4326"),map.getProjectionObject()));</div>
<div>tweetz.addFeatures([tweet.marker]);}</div>
</div>
<div><br>
</div>
<div><br>
</div>
<div><br>
</div>
<br>
<div class="gmail_quote">On Mon, Jun 20, 2011 at 9:13 PM, Phil
Scadden <span dir="ltr"><<a href="mailto:p.scadden@gns.cri.nz" target="_blank"></a><a href="mailto:p.scadden@gns.cri.nz" target="_blank">p.scadden@gns.cri.nz</a>></span>
wrote:<br>
<blockquote class="gmail_quote" style="margin:0pt 0pt 0pt 0.8ex;border-left:1px solid rgb(204, 204, 204);padding-left:1ex">I have no idea what the object returned
by twitter is but surely, but if<br>
you are using jsonp, then<br>
have in your code something like:<br>
jsonp_function(json)<br>
where jsonp_function is the name of jsonp callback and json
is the<br>
returned object. I would guess it contains an array of
feature type<br>
objects, so you would iterate through the array, creating
feature for<br>
each row, and calling vectorLayer.addFeatures(features) to
add them to<br>
the vector layer.<br>
<br>
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Atle Frenvik Sveen
Utvikler
Geomatikk IKT AS
tlf: 45 27 86 89
<a href="mailto:atle.frenvik.sveen@geomatikk.no" target="_blank"></a><a href="mailto:atle.frenvik.sveen@geomatikk.no" target="_blank">atle.frenvik.sveen@geomatikk.no</a></pre>
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