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I suppose it could work if we added the number of sides down in the
line that provides "<b> for (x = 0; x <= 360; x+=6)</b>".
Probably needs more tweaking to get squares and triangles to look
like we expect.<br>
<br>
I'm not sure how many folks besides me need this, but if there's a
perceived need, I'm willing to tune it up.<br>
<br>
oops. Just noticed in the code that I use my shorthand definition
of pt=new OpenLayers Point. fixing code below<br>
<br>
Michael<br>
<br>
On 6/28/2011 6:33 AM, Janis Elmeris wrote:
<blockquote cite="mid:4E09D839.7010108@intelligentsystems.lv"
type="cite">
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<font size="-1"><font face="Verdana">It would be a good idea to
add this function to OpenLayers.Geometry.Polygon along with
createRegularPolygon that is already there. Something like
createGeodesicRegularPolygon as there is getGeodesicArea.<br>
<br>
Janis<br>
</font></font><br>
On 2011.06.06. 8:20, Michael wrote:
<blockquote cite="mid:4DEC6399.4040306@yachtpc.com" type="cite">
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Regular Polygons are fine for many applications. I needed range
rings for ocean races, which did not correctly reflect the
projection of the map. Although it projected like a nice round
circle, the correct shape should have been oval.<br>
<br>
Did not find a geographic circle function in OL, so I adapted
one from one found online.<br>
<br>
I present it here should anyone want it, or have a better idea,
or want to point out that this was in OL all along.<br>
<br>
<b>function GeoCircle(latin, lonin, radius)// thanks to VE site
for basic algo. Returns an OL Polygon of diameter in nautical
miles<br>
{<br>
var locs = new Array();<br>
var lat1 = latin * Math.PI/180.0;<br>
var lon1 = lonin * Math.PI/180.0;<br>
var d = radius/3440.07;// change this value to the radius
of the Earth in your units<br>
var x;<br>
for (x = 0; x <= 360; x+=6) //gives 60 points. More
than enough for a smooth circle most likely<br>
{<br>
var tc = (x / 90)* Math.PI / 2;<br>
var lat =
Math.asin(Math.sin(lat1)*Math.cos(d)+Math.cos(lat1)*Math.sin(d)*Math.cos(tc));<br>
lat = 180.0 * lat / Math.PI;<br>
var lon;<br>
if (Math.cos(lat1)==0)<br>
{<br>
lon=lonin; // endpoint a pole<br>
}<br>
else<br>
{<br>
lon = ((lon1 - Math.asin(Math.sin(tc) *
Math.sin(d)/Math.cos(lat1)) + Math.PI) % (2 * Math.PI)) -
Math.PI;<br>
}<br>
lon = 180.0 * lon / Math.PI;<br>
var loc = new OpenLayers.Point(lon,lat);<br>
locs.push(loc);<br>
}<br>
var poly = new OpenLayers.Feature.Vector(new
OpenLayers.Geometry.Polygon(new
OpenLayers.Geometry.LinearRing(locs)));<br>
<br>
return poly; //this can be added to a map<br>
}<br>
</b><br>
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