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Hi Curt<br>
<br>
Yes, as I recall (and I will dig into my code as soon as I pay
bills) a copy is constructed. So you need to walk through the
points in the line itself and find the one that matches the one you
want to change (I gave them all ids). THEN change it, THEN redraw
the line. If you are doing a lot of lines or points, do them all
then redraw the layer.<br>
<br>
Michael<br>
<br>
On 4/12/2012 9:36 AM, Curtis Olson wrote:
<blockquote
cite="mid:CAHtsj_cFW4w_Mmm00cC1=+Epxza-sY-fEk2ba=3t0dOyBuf7Hw@mail.gmail.com"
type="cite">Hi Michael (and everyone else who replied),
<div><br>
Thanks for your quick replies. I'm working on this some more
today and have some follow up questions.</div>
<div><br>
</div>
<div>I define my point list in the global scope:</div>
<div><br>
<div>
<div>var route_points = new Array();<br>
<br>
</div>
<div>Then I populate this array with a few points.</div>
<div><br>
</div>
<div>Finally I can build the structures and add the result to
a layer so I can see it (and I do see the result.)</div>
<div><br>
</div>
<div>
<div>lineString = new
OpenLayers.Geometry.LineString(route_points);</div>
<div>route_vector = new
OpenLayers.Feature.Vector(lineString,null,home_style);</div>
<div>routeLayer.addFeatures( route_vector );</div>
</div>
<div><br>
</div>
<div>Later I go back and change the location of a point in my
route_list array of points.</div>
<div><br>
</div>
<div>route_points[2].lon = newlon;</div>
<div>route_points[2].lat = newlat;</div>
<div><br>
</div>
<div>But nothing changes on screen. (for what it's worth, I
can recreate all these structures and add them as a new
layer to my map and I do see the new points in their correct
locations, but it's as a new feature along with the old --
I'm hoping to be able to simply modify the old structure
rather than having to create a new (potentially
large/complex) structure each iteration.</div>
<div><br>
</div>
<div>I am wondering if the lineString or the Vector
constructors use a copy of the upstream structure rather
than a pointer to the structure? In that case changing my
original structure would have no effect.</div>
<div><br>
</div>
<div>I wouldn't mind using accessor functions to find the
actual data point, but as I look through the class
definitions and inheritance, I don't see any way to get back
to the original point array when starting from a Vector() or
a LineString()?</div>
<div><br>
</div>
<div>I'm probably missing something stupid or easy, but I'm
just not seeing it? Am I on the right track or missing by a
mile?</div>
<div><br>
</div>
<div>Thanks,</div>
<div><br>
</div>
<div>Curt.</div>
<div>
<br>
</div>
<div><br>
</div>
<div><br>
</div>
<div class="gmail_quote">On Wed, Apr 11, 2012 at 2:22 PM,
Michael <span dir="ltr"><<a moz-do-not-send="true"
href="mailto:mdm@yachtpc.com">mdm@yachtpc.com</a>></span>
wrote:<br>
<blockquote class="gmail_quote" style="margin:0 0 0
.8ex;border-left:1px #ccc solid;padding-left:1ex">
<div bgcolor="#FFFFFF" text="#000000"> Both are doable.
You need to do a little digging to be sure you are
pointing to the correct point when you either change its
lonlat or delete it. Then you need to redraw the line.<br>
<br>
In my application, I maintained a separate array
pointing to the points in my line. Possibly not the
most efficient, but it worked.<br>
<br>
Michael
<div>
<div class="h5"><br>
<br>
On 4/11/2012 12:08 PM, Curtis Olson wrote: </div>
</div>
<blockquote type="cite">
<div>
<div class="h5">
<div>Hi,</div>
<div><br>
</div>
I've begun my plunge into openlayers and have a
number of things working, but I've run into a
question that I haven't been able to answer for
myself from the docs and the mailing list
archives.
<div> <br>
</div>
<div>I am building a map that will live track an
object (for example: my aircraft location as I
fly in the FlightGear flight simulator.)</div>
<div><br>
</div>
<div>I would like to leave a trail behind myself
showing my recent path (say for the past 10
seconds or the past 10 minutes.) I am imagining
a LineString where I can insert new points at
one end and remove points from the other end --
as my position updates.</div>
<div><br>
I could create an entirely new LineString and
Vector and add that to my layer 10x a second
(removing the old feature), but I was hoping I
could just build the linestring once, add it too
a layer once, and from then on just modify the
linestring structure.</div>
<div><br>
Is something like this possible or am I barking
up the wrong tree?</div>
<div><br>
</div>
<div>I have another sort of similar situation
where I may want to additionally modify the
point locations of some of the points in the
linestring (based on external data coming from
the flight simulator.) In otherwords I want to
reshape the linestring by adjusting the
locations of individual points. Is anything
like this possible?</div>
<div><br>
I've been hunting through the examples and the
documentation and haven't stumbled on the
appropriate magic yet.</div>
<div><br>
</div>
<div>Any tips or pointers or nudges for an
openlayers newbie?</div>
<div> <br>
Thanks,</div>
<div><br>
</div>
<div>Curt.<br>
-- <br>
<div>
<div>Curtis Olson:</div>
<div><a moz-do-not-send="true"
href="http://www.atiak.com"
target="_blank">http://www.atiak.com</a> -
<a moz-do-not-send="true"
href="http://aem.umn.edu/%7Euav/"
target="_blank">http://aem.umn.edu/~uav/</a></div>
<div><a moz-do-not-send="true"
href="http://www.flightgear.org"
target="_blank">http://www.flightgear.org</a>
- <a moz-do-not-send="true"
href="http://gallinazo.flightgear.org"
target="_blank">http://gallinazo.flightgear.org</a></div>
</div>
<br>
</div>
<br>
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<br clear="all">
<div><br>
</div>
-- <br>
<div>
<div>Curtis Olson:</div>
<div><a moz-do-not-send="true" href="http://www.atiak.com"
target="_blank">http://www.atiak.com</a> - <a
moz-do-not-send="true" href="http://aem.umn.edu/%7Euav/"
target="_blank">http://aem.umn.edu/~uav/</a></div>
<div><a moz-do-not-send="true"
href="http://www.flightgear.org" target="_blank">http://www.flightgear.org</a>
- <a moz-do-not-send="true"
href="http://gallinazo.flightgear.org" target="_blank">http://gallinazo.flightgear.org</a></div>
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