Hi Olivier and Steve,
I try to follow your way but it din't work <img class='smiley' src='http://n6.nabble.com/images/smiley/anim_crazy.gif' /> It's sure I have forgot something ...
http://pofableau.com/openlayer/multicouche.html
the overlay code is ok for <b>depart</b> and <b>calque </b>but without possibility to scaling with panZoom.
It's the pb exposed in the beginning of this topic.
the overlay <b>départ2</b> who use your recommandation isn't visible on the map<img class='smiley' src='http://n6.nabble.com/images/smiley/smiley_unhappy.gif' />
I use this code :
<b><pre>
var style = new OpenLayers.Style(
OpenLayers.Util.applyDefaults(
{fillColor: "green", fillOpacity: 1, strokeColor: "black"},
{
rules: [
new OpenLayers.Rule({
maxScaleDenominator: 200000000,
minScaleDenominator: 100000000,
symbolizer: {
externalGraphic: 'a_img/travauxorange.png',
graphicHeight: 60*18/10 ,
graphicWidth: 65*18/10
}
}),
new OpenLayers.Rule({
maxScaleDenominator: 100000000,
symbolizer: {
externalGraphic: 'a_img/travauxorange.png',
graphicHeight: 60*18/5,
graphicWidth: 65*18/5
}
})
]
}));
var depart = new OpenLayers.Layer.Vector("Depart", {
styleMap: new OpenLayers.StyleMap(style) });
map.addLayer(depart);
</pre></b>
Steve I wrote the following code for <b>depart</b> and <b>calque</b> but there is no change for scale the Image as you can see. May be It's necessary to have a time out for the script ?
<b><pre>
var z= map.getScale();
var graphicWidth = 55;
var graphicHeight = 50;
var scaleFactorWidth = graphicWidth * z;
var scaleFactorHeight = graphicHeight * z;
var depart2 = new OpenLayers.Layer.Vector("Départ2");
var feature = new OpenLayers.Feature.Vector(
new OpenLayers.Geometry.Point(2.534000,48.387000).transform(
new OpenLayers.Projection("EPSG:4326"), // transform from WGS 1984
new OpenLayers.Projection("EPSG:900913") // to Spherical Mercator Projection
),
{some:'data'},
{externalGraphic: 'a_img/travauxorange.png', graphicHeight: graphicHeight, graphicWidth: scaleFactorWidth});
depart2.addFeatures(feature);
</pre>
</b>
Thank a lot for your help.
Christian
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