[Qgis-developer] Python CSV Plugin

[Tim Sutton]

Hi Jude


On Wed, Dec 29, 2010 at 9:11 AM, jude mwenda <judemwenda at gmail.com> wrote:
> Hi all,
>
> I have been building a plugin and reached a dead end. I am parsing the csv
> resource into a variable. but according to the qgis documentation, the
> resource has to be a file. Can it be a variable. the code section that has
> this issue is
>     results = ft_client.query(SQL().select(371443,None,None))
>
>     uri = results."?delimiter=%s&xField=%s&yField=%s" % (",", "Address",
> "LONGITUDE")
>     vlayer = QgsVectorLayer(uri, "layer_name_you_like", "delimitedtext")
> there is something very wrong with the uri section of the code. the docs
> just use file paths, what of a variable as is my case? How would i go about
> loading this. Please help


Possibly your issue arises from the fact that you cannot perform sql
type queries on delimited text layers. Try add a delimited layer to
QGIS interactively and you will see the Layer->Query option for that
layer is disabled.

Regards

Tim

> --
> Regards,
>
> Jude Mwenda
> Skype id: jmwenda
> Twitter: www.twitter.com/judemwenda
>
> "Was ist mein Leben, wenn ich nicht mehr nützlich für andere."
> Johann Wolfgang von Goethe
>
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>
>



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Tim Sutton - QGIS Project Steering Committee Member (Release  Manager)
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