[fdo-users] How to get feature class extent
Dan Stoica
dan.stoica at autodesk.com
Thu May 22 09:50:30 EDT 2008
Yes, is the SpatialExtent() aggregate function.
This function has been optimized for many providers in order to avoid brute force calculation (i.e. full geometries scan).
Each provider has its specifics so the optimizations are different. I can provide more details if needed.
The spatial context is useless for another reason: it doesn't give you the exact extent. For example, in Lat/Long it is common to set the extents to [(-180, -90) (180, 90)].
Dan.
-----Original Message-----
From: fdo-users-bounces at lists.osgeo.org [mailto:fdo-users-bounces at lists.osgeo.org] On Behalf Of Bruno Scott
Sent: Thursday, May 22, 2008 9:38 AM
To: fdo-users at lists.osgeo.org
Subject: [fdo-users] How to get feature class extent
Is there a way to get the actual extent of a feature class.
I know we can get the spatial context associated with that class and request
it's extent.
But as many feature class can share the same spatial context, it's not the
actual result i'm interested in.
Thanks Bruno Scott
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