[gdal-dev] Reprojection raster 0 360 longitude

[Eloi Ribeiro]

Try this to convert 0º 360º into -180º 180º:
http://eloiribeiro.wordpress.com/2009/07/08/coverter-imagens-0%C2%BA-360%C2%BA-a-180-180%C2%BA-com-gdal/
Good luck,

Eloi Ribeiro
GIS Analyst / Programmer
51.9871, 5.6661
flavors.me/eloiribeiro


On 7 June 2013 17:32, laura0 <lauramail at iol.it> wrote:

> Hi all,
> I have a geotiff with the following corner coordinates:
> Upper Left  (  -0.2500000,  90.2500000) (  0d15' 0.00"W, 90d15' 0.00"N)
> Lower Left  (  -0.2500000, -90.2500000) (  0d15' 0.00"W, 90d15' 0.00"S)
> Upper Right (     359.750,      90.250) (359d45' 0.00"E, 90d15' 0.00"N)
> Lower Right (     359.750,     -90.250) (359d45' 0.00"E, 90d15' 0.00"S)
> Center      ( 179.7500000,   0.0000000)
>
> I would like to reproject it in UTM (then I will crop the image) for
> instance with the command
> gdalwarp -t_srs "+proj=utm +zone=32 +datum=WGS84" temp.tif proj.tif
>
> As you can see above, the range of longitude is 0 360 and not -180 180 so I
> have tried:
> gdalwarp -t_srs "+proj=utm +zone=32 +datum=WGS84" -te -180 -90 180 90
> temp.tif proj.tif
> but I get the error message
>  ERROR 1: Reprojection failed, err = -14, further errors will be supressed
> on the transform object.
> Creating output file that is 0P x 0L.
>
> I have also tried the option -wo SOURCE_EXTRA=1000 --config CENTER_LONG 0 I
> have found somewhere, but I am not sure this is the right way.
> Can someone suggest me the way?
> Thanks
>
> Laura
>
>
>
> --
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> http://osgeo-org.1560.x6.nabble.com/Reprojection-raster-0-360-longitude-tp5058766.html
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