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<p class=MsoNormal><font size=2 color=navy face=Arial><span style='font-size:
10.0pt;font-family:Arial;color:navy'>Thanks to everybody for the replies. I had
actually found the formula for distance between <o:p></o:p></span></font></p>
<p class=MsoNormal><font size=2 color=navy face=Arial><span style='font-size:
10.0pt;font-family:Arial;color:navy'>two lat-lon coordinates on this page. If
only I’d scrolled down a little bit, I’d have found this <o:p></o:p></span></font></p>
<p class=MsoNormal><font size=2 color=navy face=Arial><span style='font-size:
10.0pt;font-family:Arial;color:navy'>formula!<o:p></o:p></span></font></p>
<p class=MsoNormal><font size=2 color=navy face=Arial><span style='font-size:
10.0pt;font-family:Arial;color:navy'><o:p> </o:p></span></font></p>
<p class=MsoNormal><font size=2 color=navy face=Arial><span style='font-size:
10.0pt;font-family:Arial;color:navy'>Allan<o:p></o:p></span></font></p>
<p class=MsoNormal><font size=2 color=navy face=Arial><span style='font-size:
10.0pt;font-family:Arial;color:navy'><o:p> </o:p></span></font></p>
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<p class=MsoNormal><b><font size=2 face=Tahoma><span style='font-size:10.0pt;
font-family:Tahoma;font-weight:bold'>From:</span></font></b><font size=2
face=Tahoma><span style='font-size:10.0pt;font-family:Tahoma'> Lennox Antoine
[mailto:lxnyce@gmail.com] <br>
<b><span style='font-weight:bold'>Sent:</span></b> January 28, 2008 8:46 PM<br>
<b><span style='font-weight:bold'>To:</span></b> Ray Gardener<br>
<b><span style='font-weight:bold'>Cc:</span></b> <st1:PersonName w:st="on">Meek,
Allan</st1:PersonName> (Contractor); gdal-dev@lists.osgeo.org<br>
<b><span style='font-weight:bold'>Subject:</span></b> Re: [gdal-dev] Lat/long
& distance/heading calculation</span></font><o:p></o:p></p>
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<p class=MsoNormal><font size=3 face="Times New Roman"><span style='font-size:
12.0pt'><o:p> </o:p></span></font></p>
<p class=MsoNormal style='margin-bottom:12.0pt'><font size=3
face="Times New Roman"><span style='font-size:12.0pt'>This might be what you're
looking for : <a href="http://www.movable-type.co.uk/scripts/latlong.html">http://www.movable-type.co.uk/scripts/latlong.html</a><br>
<br>
Look for the section : <b><span style='font-weight:bold'>Destination point
given distance and bearing from start point<br>
<br>
</span></b>-<st1:place w:st="on">Lennox</st1:place><o:p></o:p></span></font></p>
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<p class=MsoNormal><font size=3 face="Times New Roman"><span style='font-size:
12.0pt'>On Jan 28, 2008 7:55 PM, Ray Gardener <<a
href="mailto:rayg@daylongraphics.com">rayg@daylongraphics.com</a>> wrote:<o:p></o:p></span></font></p>
<p class=MsoNormal><font size=3 face="Times New Roman"><span style='font-size:
12.0pt'>If you can use UTM or similar coords, then<br>
<br>
x = cos(heading) * distance + start_pos_x<br>
y = sin(heading) * distance + start_pos_y<br>
<br>
Assuming heading in clockwise radians with north = up.<br>
<br>
Then you can inverse transform (x, y) from UTM to lat/lon.<br>
<font color="#888888"><span style='color:#888888'><br>
Ray</span></font><o:p></o:p></span></font></p>
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<br>
<br>
<o:p></o:p></span></font></p>
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