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Sorry, tomorrow in the morning pass you the entire code and the value of pixelFormat__1 because the code is in my office.<div><br></div><div>Thanks for your reply.</div><div><br></div><div>Francisco J.</div><div><div><br><hr id="stopSpelling">Date: Tue, 19 Apr 2011 16:10:27 +0200<br>Subject: Re: [gdal-dev] Problem with GDALDatasetRasterIO.cs and ECW files<br>From: szekerest@gmail.com<br>To: gistdt08@hotmail.es<br>CC: gdal-dev@lists.osgeo.org<br><br>Not sure what is the actual value of 'pixelFormat__1' in your program.<br><br>Best regards,<br><br>Tamas<br><br><br><div class="ecxgmail_quote">2011/4/19 Francisco José Reyes Peralta <span dir="ltr"><<a href="mailto:gistdt08@hotmail.es">gistdt08@hotmail.es</a>></span><br>
<blockquote class="ecxgmail_quote" style="border-left:1px #ccc solid;padding-left:1ex">
<div>
<pre style="font-family:'Times New Roman';font-size:12pt">The parameter is not valid is the error that I get.</pre><pre style="font-family:'Times New Roman';font-size:12pt">I use an adaptation of the source .cs code in <a href="http://VB.NET" target="_blank">VB.NET</a>.</pre>
<pre style="font-family:'Times New Roman';font-size:12pt">Here is part of the code:</pre><pre><span style="font-size:21px"><br></span></pre><pre><font size="4"> Dim pixelFormat As PixelFormat</font></pre><pre><font size="4"><span style="white-space:pre-wrap"> </span>Dim dataType As DataType
Dim pixelSpace As Integer
If isIndexed Then
pixelFormat = PixelFormat.Format8bppIndexed
dataType = DataType.GDT_Byte
pixelSpace = 1
Else
If channelCount = 1 Then
If channelSize > 8 Then
pixelFormat = PixelFormat.Format16bppGrayScale
dataType = DataType.GDT_Int16
pixelSpace = 2
Else
pixelFormat = PixelFormat.Format24bppRgb
channelCount = 3
dataType = DataType.GDT_Byte
pixelSpace = 3
End If
Else
If hasAlpha Then
If channelSize > 8 Then
pixelFormat = PixelFormat.Format64bppArgb
dataType = DataType.GDT_UInt16
pixelSpace = 8
Else
pixelFormat = PixelFormat.Format32bppArgb
dataType = DataType.GDT_Byte
pixelSpace = 4
End If
channelCount = 4
Else
If channelSize > 8 Then
pixelFormat = PixelFormat.Format48bppRgb
dataType = DataType.GDT_UInt16
pixelSpace = 6
Else
pixelFormat = PixelFormat.Format24bppRgb
dataType = DataType.GDT_Byte
pixelSpace = 3
End If
channelCount = 3
End If
End If
End If
<b><span style="font-weight:normal"><b><span style="font-family:'Times New Roman';font-weight:normal;white-space:normal;font-size:medium"><pre style="text-indent:0px !important;font-family:'Times New Roman';font-size:12pt;display:inline !important">And the Error is in the following line:</pre></span></b></span></b></font></pre><pre><font size="4">
Dim bitmap As New Bitmap(imageWidth, imageHeight, pixelFormat__1)</font></pre><pre><font size="4"><br></font></pre><pre><font size="4"><font face="'Times New Roman'">Is possible to read the dataset and write to a bitmap or picturebox without save as file?</font></font></pre>
<pre><font size="4"><font face="'Times New Roman'"><br></font></font></pre><pre><font size="4">Thanks for your reply.</font></pre><pre><font size="4"><br></font></pre><pre><font size="4">Francisco J.</font></pre><pre><font size="4"><br></font></pre><pre><font size="4"><br></font></pre><pre style="font-family:'Times New Roman';font-size:12pt">2011/4/19 Francisco José Reyes Peralta <<a href="http://lists.osgeo.org/mailman/listinfo/gdal-dev" target="_blank">gistdt08 at hotmail.es</a>>
><i> Dear friends, I'm vieweing the *GDALDatasetRasterIO.cs* from the Csharp
</i>><i> samples of GDAL and I'm getting an error in the following line *Bitmap
</i>><i> bitmap = new Bitmap(imageWidth, imageHeight, pixelFormat);* In the *
</i>><i> pixelFormat* argument.
</i>><i>
</i>
Hi,
What is the error message specifically?
Best regards,
Tamas
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