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The docs say that the return value of GetName() <br>
<blockquote>should be sufficient to open the data source if passed
to the same <a class="el">OGRSFDriver</a> that this data source
was opened with, but it need not be exactly the same string that
was used to open the data source.<br>
</blockquote>
Looking at your code snippet I'm guessing that
/home/nyall/dev/QGIS/tests is the current working directory and the
return value is relative to that path, hence just the bare
filename. I'd suggest testing with a file not located in the
working directory and see if you get a full path (or a path relative
to the working directory). Unfortunately the laptop I'm mailing from
doesn't have GDAL/OGR installed, so I can't test this myself. <br>
<br>
David<br>
<br>
On 6/10/2019 10:17 PM, Nyall Dawson wrote:
<blockquote type="cite">
<pre class="moz-quote-pre" wrap="">Hi list,
If I have a bunch of say shapefiles in a folder, OGR is happy to let
me access these as a dataset, e.g.
da = r"/home/nyall/dev/QGIS/tests/testdata"
driver = ogr.GetDriverByName('ESRI Shapefile')
dataSource = driver.Open(da, 0)
for i in dataSource:
print(i.GetName())
My question is -- GetName() here returns just the file base name (i.e.
"lines" for "/path/lines.shp"). Is there anyway to retrieve the actual
layer file path for these?
Nyall
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</blockquote>
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