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<div class="moz-cite-prefix">Hi</div>
<div class="moz-cite-prefix"><br>
</div>
<div class="moz-cite-prefix">Have you tested PostGIS?</div>
<div class="moz-cite-prefix">ST_ExteriorRing((ST_Dump(ST_LineMerge(ST_Union(ST_Force2D(<your
geometry>))))).geom)</div>
<div class="moz-cite-prefix"><br>
</div>
<div class="moz-cite-prefix">should extract the points you want to
keep by splitting at intersections - but it may fail in very
complex cases. Then I would start with a ST_SnapToGrid with a
quite high tolerance to lower the coordinate resolution.<br>
<br>
</div>
<div class="moz-cite-prefix"><br>
</div>
<blockquote type="cite"
cite="mid:aeff7777-d05b-415c-e2d6-cb7ff62bac83@gmail.com">
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<p>Hi,</p>
<p>I wrote a method to a Polygon class (in Python) that solves
that problem because the ones in GEOS via Shapely did not seem
good enough. My method was based on no published algorithm but
just my own reasoning, it is probably not optimal speed-wise. I
did not perform formal testing on it but it worked on my data,
which was quite large. The basic idea was to build the polygon
by adding points and when adding test for self intersections /
collinearity against existing segments. The method returns the
loops while points are added. The code is not in a public repo
but I'll add the method below. It needs some basic methods and
function which should be simple to add.<br>
</p>
<p>Ari<br>
</p>
<div class="moz-cite-prefix">Chao YUE kirjoitti 15.4.2020 klo
6.30:<br>
</div>
<blockquote type="cite"
cite="mid:CAAN-aRFQsyoVTBceU0QhGcoPr-obmeVhUujAccYroaJwBBPUCw@mail.gmail.com">
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<div>Dear all,</div>
<div><br>
</div>
<div>Does anyone have some experience or is aware of some
algorithm that can find and clip the inner loop formed in
a polygon ? I attach one example here. In this case I
would only keep the outer points and drop the ones that
make an inner loop. I am developing some algorithm to
simulate wildland fire propagation. The algorithm is based
on Richards 1990.</div>
<div><br>
</div>
<div>In the paper he described an algorithm based on two
steps: (1) find the points where a concave curvature is
made. (2) search for both sides of this point to see where
any two line segments cross over each other. </div>
<div>But I am wondering whether there is already some
existing solutions or other better ones. </div>
<div><br>
</div>
<div>Thanks a lot for the kind help for any hints on this !</div>
<div>Kind regards,</div>
<div>Chao</div>
<div><br>
</div>
<div>Gwynfor Richards, 1990. An elliptical growth model of
forest fire fronts and its numerical solution.
International journal for Numerical Methods in
Engineering, Vol. 30, 1163-1179.</div>
<div><br>
</div>
<div><img src="cid:part1.8C18B390.16925307@t-kartor.se"
alt="InnerLoop.png" class="" width="562" height="415"><br>
</div>
</div>
<div><br>
</div>
-- <br>
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data-smartmail="gmail_signature">
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<div>
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<div><span style="font-size:12.8px">***********************************************************************************</span><br>
</div>
<div><font color="#000000">Chao YUE(岳超)</font></div>
<font color="#000000">西北农林科技大学水土保持研究所 研究员</font></div>
<div dir="ltr"><font color="#000000">黄土高原土壤侵蚀与旱地农业国家重点实验室</font></div>
<div dir="ltr"><span
style="font-family:Helvetica;font-size:12px"><font
color="#000000">State Key Laboratory of
Soil Erosion and Dryland Farming on the
Loess Plateau</font></span></div>
<div dir="ltr"><span
style="font-family:Helvetica;font-size:12px"><font
color="#000000">Institute of Soil and
Water Conservation</font></span></div>
<div dir="ltr"><font color="#000000"><span
style="font-family:Helvetica;font-size:12px">Northwest
A&F University, Yangling, Shaanxi
712100, P.R. China</span><br>
</font></div>
<div dir="ltr">
<div><font color="#000000"><a
href="mailto:chaoyue@ms.iswc.ac.cn"
style="font-family:Helvetica;font-size:12px"
target="_blank" moz-do-not-send="true">chaoyue@ms.iswc.ac.cn</a><br>
</font></div>
<div><font color="#000000">Mobile: +86
18709187546</font></div>
<div>************************************************************************************<br>
</div>
</div>
</div>
</div>
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</div>
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<pre class="moz-quote-pre" wrap="">_______________________________________________
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</blockquote>
<p><br>
</p>
<p>Code copyright Simosol Oy, licence MIT<br>
</p>
<p>def add_point(self, p=None):<br>
""" Add a point to the end of points (before root)<br>
The first level ear (hole or in-a-point-intersecting
polygon) is returned<br>
if there is such.<br>
p -- point to add, if None, close the ring</p>
<p> self is a Polygon, which has as attributes a dict of
points, where<br>
point = [index of previous point, index of next point,
coords]<br>
no duplicates, no null indexes in points<br>
</p>
<p> """<br>
n = self.n_points()<br>
if p is None and n < 3:<br>
raise ValueError("Can't close a polygon with less
than three points.")<br>
if self.root is None:<br>
self.root = 0<br>
self.points[self.root] = [self.root, self.root, p]<br>
return<br>
i0 = self.points[self.root][0]<br>
if p is not None and p[0] == self.points[i0][2][0] and
p[1] == self.points[i0][2][1]:<br>
# same point, skip<br>
return None<br>
index = i0 + 1<br>
while index in self.points:<br>
index += 1<br>
ear = None<br>
close = False<br>
if n > 2:<br>
# test for self-intersection,<br>
# current - new against (0-1, )1-2, ...
prev(current)-current<br>
current_point = self.get_point(i0)<br>
j0 = self.root<br>
if p is None: # close<br>
p = self.get_point(self.root)<br>
j0 = self.index_of_next_point(j0)<br>
close = True<br>
while True:<br>
j1 = self.index_of_next_point(j0)<br>
if j1 == i0:<br>
break<br>
pj0 = self.get_point(j0)<br>
pj1 = self.get_point(j1)<br>
x = get_line_intersection(pj0, pj1,
current_point, p)<br>
<br>
if type(x) is tuple: # Intersection<br>
#print('intersection',pj0,pj1,current_point,p)<br>
# snip away and return eventually the closed
part<br>
ear = self.get_noose(j1, i0, first_point=x)<br>
# set new j1 and delete from j1+1 ...
current<br>
self.set_point(j1, x)<br>
j2 = self.index_of_next_point(j1)<br>
self.delete_points(j2, i0)<br>
i0 = j0<br>
index = j1<br>
break<br>
<br>
elif abs(x) == 1: # Collinear<br>
if point_on_line(p, pj0, pj1): # new is on
j0 - j1<br>
#print('collinear new on
j0-j1',pj0,pj1,current_point,p)<br>
# is j1 on cp - new?<br>
if point_in_box(pj1, current_point, p):<br>
k = j1 # ear is j1 ... cp<br>
else: # j0 is on cp - new<br>
k = j0 # ear is j0 ... cp<br>
ear = self.get_noose(k, i0)<br>
self.delete_points(j1, i0)<br>
i0 = j0<br>
index = j1<br>
break<br>
elif point_on_line(pj1, current_point, p): #
j1 is on cp - new<br>
#print('collinear j1 on
cp-new',pj0,pj1,current_point,p)<br>
# ear is j1 ... cp<br>
ear = self.get_noose(j1, i0)<br>
self.delete_points(j1, i0)<br>
i0 = j0<br>
index = j1<br>
break<br>
j0 = j1<br>
<br>
if not close:<br>
self.points[index] = [i0, self.root, p]<br>
self.points[i0][1] = index<br>
self.points[self.root][0] = index<br>
return ear<br>
</p>
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<pre class="moz-quote-pre" wrap="">_______________________________________________
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</blockquote>
<p><br>
</p>
<pre class="moz-signature" cols="72">--
Hälsningar
Andreas Oxenstierna
T-Kartor Geospatial AB
Olof Mohlins väg 12 Kristianstad
mobile: +46 733 206831
mailto: <a class="moz-txt-link-abbreviated" href="mailto:ao@t-kartor.se">ao@t-kartor.se</a>
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