[GRASS-dev] Reg i.pca output

[Markus Metz]

On Tue, Mar 26, 2013 at 6:37 PM, Rashad M <mohammedrashadkm at gmail.com> wrote:
> That worked.
>
> so what change the rescale option add to the transformation equation?

The rescale option rescales the output maps with the PC scores to the
given min,max range (default 0,255).

Markus M

>
>
> On Tue, Mar 26, 2013 at 7:40 PM, Markus Metz <markus.metz.giswork at gmail.com>
> wrote:
>>
>> On Tue, Mar 26, 2013 at 1:21 PM, Rashad M <mohammedrashadkm at gmail.com>
>> wrote:
>> > It seems like values are different using the forumla. I can provide a
>> > test
>> > case if you need
>> >
>> >
>> >
>> > i tried this:
>> > i.pca in=lsat7_2000_10,lsat7_2000_20 out=mypca
>> >
>> > Rescaling to range 0,255...
>> >  100%
>> > Eigen values, (vectors), and [percent importance]:
>> > PC1    436.48 ( 0.6640, 0.7477) [98.84%]
>> > PC2      5.13 (-0.7477, 0.6640) [ 1.16%]
>> >
>> >
>> > here only first column of eigen vector is important right?
>> >
>> > But let me ask does eigen values and percent of importance doesnt have
>> > any
>> > role?
>> >
>> > here when running the above i.pca i get mypca.1 and mypca.2
>> > P1 and P2 are first pixel row=0, col=0 of mypca.1 and mypca.2
>> > respectively
>> > and mean is the mean of lsat7_2000_10
>> >
>> > output is the output obtained from the equation --> (X = P *
>> > eigenvector(P,
>> > X) + P * eigenvector(Q, X) + mean(B1) )
>> >
>> > and input is the pixel value of lsat7_2000_10 @ row=0, col=0
>> >
>> >
>> > P1=  21
>> > P2=  112
>> > mean=    79.925
>> > output=  138.4471
>> > input=   72
>> >
>> > Any thoughts?
>>
>> You need to disable rescaling of the PC scores with i.pca rescale=0,0
>>
>> Markus M
>>
>> >
>> >
>> > On Tue, Mar 26, 2013 at 4:54 PM, Markus Metz
>> > <markus.metz.giswork at gmail.com>
>> > wrote:
>> >>
>> >> On Tue, Mar 26, 2013 at 12:10 PM, Rashad M <mohammedrashadkm at gmail.com>
>> >> wrote:
>> >> >
>> >> >
>> >> >
>> >> > On Tue, Mar 26, 2013 at 3:58 PM, Markus Metz
>> >> > <markus.metz.giswork at gmail.com>
>> >> > wrote:
>> >> >>
>> >> >> On Tue, Mar 26, 2013 at 10:25 AM, Rashad M
>> >> >> <mohammedrashadkm at gmail.com>
>> >> >> wrote:
>> >> >> >
>> >> >> >
>> >> >> >
>> >> >> > On Tue, Mar 26, 2013 at 2:44 PM, Markus Metz
>> >> >> > <markus.metz.giswork at gmail.com>
>> >> >> > wrote:
>> >> >> >>
>> >> >> >> On Tue, Mar 26, 2013 at 8:39 AM, Rashad M
>> >> >> >> <mohammedrashadkm at gmail.com>
>> >> >> >> wrote:
>> >> >> >> > Hi,
>> >> >> >> >
>> >> >> >> > i.pca creates 6 raster maps for 6 input raster
>> >> >> >> >
>> >> >> >> > eg:
>> >> >> >> >
>> >> >> >> > i.pca
>> >> >> >> >
>> >> >> >> >
>> >> >> >> >
>> >> >> >> >
>> >> >> >> > in=lsat7_2002_10,lsat7_2002_20,lsat7_2002_30,lsat7_2002_40,lsat7_2002_50,lsat7_2002_70
>> >> >> >> > \
>> >> >> >> >     out=lsat7_2002_pca
>> >> >> >> >
>> >> >> >> >
>> >> >> >> > I have a doubt here
>> >> >> >> >
>> >> >> >> > Does the output lsat7_2002_pca.1 is the corresponding map for
>> >> >> >> > lsat7_2002_10?
>> >> >> >>
>> >> >> >> No. lsat7_2002_pca.1 contains the principal component with the
>> >> >> >> highest
>> >> >> >> eigenvalue and is calculated using all input bands. More
>> >> >> >> generally,
>> >> >> >> each lsat7_2002_pca.* map is calculated using all input bands.
>> >> >> >> Look
>> >> >> >> at
>> >> >> >> the eigenvectors to find out the weights with which each input
>> >> >> >> map
>> >> >> >> contributes to a specific PCA.
>> >> >> >>
>> >> >> >
>> >> >> > So by knowing a pixel value of lsat7_2002_pca.1 can I get the
>> >> >> > value
>> >> >> > before
>> >> >> > transformation in PCA.
>> >> >> > consider this:
>> >> >> > I have two bands B1,B2 and after i.pca I get PC1,PC2. Then is
>> >> >> > there a
>> >> >> > way to
>> >> >> > derive value of X,Y where X belongs to B1 and Y belongs to B2 by
>> >> >> > only
>> >> >> > knowing P,Q
>> >> >> > where P belongs to PC1 and Q belongs to PC2
>> >> >> >
>> >> >> > and also X,Y and P,Q are of same index (row,col)
>> >> >>
>> >> >> X = P * eigenvector(P, X) + P * eigenvector(Q, X) + mean(B1)
>> >> >>
>> >> >> Using the example from the manual:
>> >> >>
>> >> >> X = 0.2824 * PC1 + 0.2541 * PC2 + 0.3801 * PC3 +  0.1752 * PC4 -
>> >> >> 0.6170 * PC5 - 0.5475 * PC6 + mean(band 1)
>> >> >
>> >> >
>> >> > Thanks.
>> >> >
>> >> > just a small clarification:
>> >> > PC1 is the pixel value at (i,j) of output band  pca.1 and X is the
>> >> > pixel
>> >> > value at (i,j) of input band b1
>> >> >
>> >> > This is correct?
>> >>
>> >> yes
>> >>
>> >> >
>> >> >>
>> >> >> Markus M
>> >> >>
>> >> >> >
>> >> >> > I hope this is clear
>> >> >> >
>> >> >> >>
>> >> >> >> Markus M
>> >> >> >>
>> >> >> >> >
>> >> >> >> > If so the lsat7_2002_10_pca.1 contains PCA transformed pixel
>> >> >> >> > for
>> >> >> >> > lsat7_2002_10
>> >> >> >> >
>> >> >> >> > Is this correct?
>> >> >> >> >
>> >> >> >> > --
>> >> >> >> > Regards,
>> >> >> >> >    Rashad
>> >> >> >> >
>> >> >> >> > _______________________________________________
>> >> >> >> > grass-dev mailing list
>> >> >> >> > grass-dev at lists.osgeo.org
>> >> >> >> > http://lists.osgeo.org/mailman/listinfo/grass-dev
>> >> >> >
>> >> >> >
>> >> >> >
>> >> >> >
>> >> >> > --
>> >> >> > Regards,
>> >> >> >    Rashad
>> >> >
>> >> >
>> >> >
>> >> >
>> >> > --
>> >> > Regards,
>> >> >    Rashad
>> >
>> >
>> >
>> >
>> > --
>> > Regards,
>> >    Rashad
>
>
>
>
> --
> Regards,
>    Rashad