[GRASS-dev] Parsing output of r.category which includes labels
nik at nikosalexandris.net
Mon Aug 20 17:07:41 PDT 2018
* Stefan Blumentrath <Stefan.Blumentrath at nina.no> [2018-08-20 10:48:34 +0000]:
>You could use numpy and genfromtxt() to parse the output string...
>genfromtxt() requires an StringIO object (or file) and StringIO (from io) requires unicode()...
>So you could do:
>from io import StringIO
>import numpy as np
>output = np.genfromtxt(StringIO(unicode(grass.read_command('r.category', map=base))) , delimiter='\t', dtype=None, names=['cat', 'label'])
>That causes however some overhead . So if it makes sense depends on what you want to do with the data in the further processing chain...
Thank for the idea Stefan.
This is really a small (in size) task.
I think it's not worth to use NumPy just for a few lines.
Wouldn't the major reason, to use NumPy, be speed in computations?
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