[GRASS-user] Problem with r.reclas on ubuntu feisty

[Glynn Clements]

Maciej Sieczka wrote:

> > I have problem with r.reclass (and r.reclas.rules) from latest cvs
> > (updated wensday morning)
> > on whatever map I use it I recive segmentation fault error
> 
> I confirm for current GRASS 6.3 CVS built and running on Ubuntu Dapper,
> 32 bit, GCC 4.0.3, Pentium M, kernel 2.6.15-28-686.
> 
> Any r.reclass session ends up with a segfault after the 'end' command;
> eg. in spearfish:
> 
> $ r.reclass in=aspect output=tryit
> 
> > 1 thru 9.9 = 1
> 10.400000 rounded up to 10
> > 30 thru 31 = 32
> > end
> Segmentation fault

I changed the name/mapset fields in struct Reclass from fixed-size
char[] to dynamically-allocated char*. I missed some of the cases
which were relying upon the old structure (AFAICT, I got all of the
ones in libgis, but missed r.reclass).

This should be sufficient for r.reclass:

--- raster/r.reclass/reclass.c	15 Dec 2006 09:05:02 -0000	2.2
+++ raster/r.reclass/reclass.c	25 Apr 2007 22:49:33 -0000
@@ -200,8 +200,8 @@
 {
     struct Reclass mid;
 
-    strcpy(mid.name, input_name);
-    strcpy(mid.mapset, input_mapset);
+    mid.name = G_store(input_name);
+    mid.mapset = G_store(input_mapset);
 
     _reclass(rules, cats, &mid);
 
@@ -225,14 +225,14 @@
 
     if (is_reclass)
     {
-	strcpy (new.name, old.name);
-	strcpy (new.mapset, old.mapset);
+	new.name = G_store(old.name);
+	new.mapset = G_store(old.mapset);
 	re_reclass (rules, cats, &old, &new, old_name, old_mapset);
     }
     else
     {
-	strcpy (new.name, old_name);
-	strcpy (new.mapset, old_mapset);
+	new.name = G_store(old.name);
+	new.mapset = G_store(old.mapset);
 	_reclass (rules, cats, &new);
     }
 

Now I need to go through and see what else I might have missed.

> Why "10.400000 rounded up to 10". I specified range "1 thru 9.9"...
>  Maciek

Reclassing only works on integers; FP maps have to be quantised. This
is done by rounding to the nearest integer, i.e. adding 0.5 then
truncating. The code which prints the message uses the value after the
0.5 has been added to it. I'll look into that later.

-- 
Glynn Clements <glynn at gclements.plus.com>