[GRASS-dev] Re: [GRASS-user] Get current location projection in a Python Script

[Nikos Alexandris]

On Tuesday 01 of June 2010 05:46:22 Glynn Clements wrote:
> Markus Neteler wrote:
> > >>     # faster/ easier way: use of the "grass.region()" function
> > >>     rows = int(grass.region()['rows'])
> > >>     cols = int(grass.region()['cols'])
> > > 
> > > In 7.0, these fields are already integers; r40555 should be
> > > backported.
> > 
> > AFAIK it has been backported some time ago.
> > 
> > http://trac.osgeo.org/grass/browser/grass/branches/releasebranch_6_4/lib/
> > python/core.py#L503
> 
> Okay; change that to "I should 'svn update' the other branches more
> often", then ;)

This means it should be like:

rows = grass.region()['rows']
cols = grass.region()['cols']

Right?

Nikos