[GRASS-user] Get current location projection in a Python Script
Michael Barton
Michael.Barton at asu.edu
Sun May 30 06:52:37 EDT 2010
Thanks. Quite helpful.
Michael
____________________
C. Michael Barton
Director, Center for Social Dynamics & Complexity
Professor of Anthropology, School of Human Evolution & Social Change
Arizona State University
voice: 480-965-6262 (SHESC), 480-727-9746 (CSDC)
fax: 480-965-7671 (SHESC), 480-727-0709 (CSDC)
www: www.public.asu.edu/~cmbarton, http://csdc.asu.edu
On May 30, 2010, at 2:41 AM, Nikos Alexandris wrote:
> [...]
>
> Nikos Alexandris:
>>>>> Just for the records, a thread not _directly_ about it but close
>>>>> (enough?):
>>>>> <http://osgeo-org.1803224.n2.nabble.com/Getting-rows-cols-of-a-region-i
>>>>> n -a- script-tc2787474.html#a2788062>
> [...]
>>> 1. http://www.mail-archive.com/grass-user@lists.osgeo.org/msg08280.html
>>> 2. http://www.mail-archive.com/grass-user@lists.osgeo.org/msg08288.html
>
> Michael Barton wrote:
>> These work, but there is a better shortcut now from the GRASS Python
>> library.
>
>> regiondict = grass.region()
>
>> will create a Python dictionary regiondict with values for extents and
>> resolution. It's the same as creating a dictionary by parsing g.region
>> -ugp
>
> Attached a simple python script with various ways to get "rows, cols" from the
> "current" region.
>
> Nikos
> <g.region.resolution.py>
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