[mapserver-users] is this possible or does this need to be a feature request

Rodrigo Cabral cabral at yadata.net
Sat Feb 16 11:57:02 EST 2002


On the other hand, you could put your data in an Oracle SDO database, and
define a LAYER to display the result of a SDO_GEOM.SDO_BUFFER function like
in:

LAYER
CONNECTIONTYPE oraclespatial
CONNECTION 'username/password at db'
DATA "buffer FROM (SELECT sdo_geom.sdo_buffer( table.shape, <distance>,
<tolerance> ) AS buffer FROM table)"
STATUS default
TYPE polygon
# more layer stuff like classes, etc
END

There you have your buffer shapes on-the-fly! No PHP/MapScript needed, you
can use the CGI version if you wish... Pretty cool isn't it? =)

Cheers,
Rod.

----- Original Message -----
From: "Stephen Woodbridge" <woodbri at swoodbridge.com>
To: "kenboss" <kenboss at philbert.dnr.state.mn.us>; "MapServer List"
<mapserver-users at lists.gis.umn.edu>
Sent: Friday, February 15, 2002 6:41 PM
Subject: Re: [mapserver-users] is this possible or does this need to be a
feature request


Oops, Ken points out a big oversight on my part, looks-like you can
ignore point 2 in my response as it looks like you can already do a
querybyshape that is a polygon.

Thanks, Ken.
  -Steve

kenboss wrote:
>
> I can't speak to the buffering part (I will be interested to see what
others
> have to say on that), but the polygon query part is already available in
> mapscript through the (either map or layer) queryByShape method.  A quick
look
> at http://mapserver.gis.umn.edu/doc/cgi-reference.html seems to indicate
that
> this should be possible in the cgi version as well, using MAPSHAPE or
IMGSHAPE
> and with the NQUERY mode.
>
> --Ken Boss
>
> > Fred,
> >
> > Steve Lime may want to jump in on this to add or correct this.
> >
> > I see two issues here:
> >
> > 1) You have to construct and offset polygon (unless you are willing to
> > accept the rectangular extents of the polygon). This is pretty straight
> > forward:
> >   a) pick the first edge and determine which side is outside of the
> >      polygon
> >   b) construct an offset line on the outside of the first segment
> >   c) construct an offset line for each successive segment and intersect
> >      it with the previous segment and save the intersection point, you
> >      also have to check and handle concave angles where the offsets
> >      eliminate the edges totally.
> >   d) then build a new poygon form the intersection points.
> >
> > 2) currently (I believe) the query code ONLY works for points and
> > rectangles. Modifing query code to do queries of arbitrary polygons
> > would be possible but require some additional computations like:
> >   a) first check that the extents of the obj and the query polygon
> >      overlap.
> >   b) if point, see if it is inside the query polygon
> >      if line,  see if it intersects the query polygon
> >      if polygon, polyline, see if extents are all inside or the extents
> >         intersect with the query polygon
> >        if extents intersect see if any edge intersects with the query
> >           polygon
> >          if not, see if all vertices are inside the query polygon
> >
> > You could do all of this in mapscript, but might be very slow if you
> > have lots of polygons or the polygon have lots of points. Also you have
> > to be able to deal with multipart objects. There may be some code
> > already in mapserver that can be adapted to some parts of this as
> > rotated label extents represent 5 node convex polygons.
> >
> > Anyway, I hope this helps,
> >   -Steve Woodbridge
> >
> > Fred McDavid wrote:
> > >
> > > What I'm wanting to do is:
> > >
> > > take a polygon from one layer, using that polygon and some function
(in
> > > this case, one that would add a "buffer" to the original polygon) come
> > > up with a new polygon, then draw that polygon and/or use it to query
> > > layers.
> > >
> > > I'm wondering if there is presently a way to do this and, if not, what
> > > obstacles (WRT design issues) would I face if I tried to make
mapserver
> > > and/or php-mapscript do this?
> > >
> > > Regards,
> > >
> > > Fred




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