Formula for converting pixels to long lat points

[Abe Gillespie]

Yes, one would expect you'd take a *little* initiative in solving your
problems.  :)

-Abe

On Dec 6, 2004, at 3:54 PM, Ed McNierney wrote:

> Joseph -
>
> I'm wondering whether this is the MapServer list or the elementary
> algebra list <g>.  Last time I looked, if:
>
> LONG = MINX + (X * DPP)
>
> Then
>
> (LONG - MINX) / DPP = X
>
>         - Ed
>
> Ed McNierney
> President and Chief Mapmaker
> TopoZone.com / Maps a la carte, Inc.
> 73 Princeton Street, Suite 305
> North Chelmsford, MA  01863
> ed at topozone.com
> (978) 251-4242
>
> -----Original Message-----
> From: Joseph Norris [mailto:sirronj at pacbell.net]
> Sent: Monday, December 06, 2004 3:42 PM
> To: Ed McNierney; MAPSERVER-USERS at lists.umn.edu
> Subject: RE: [UMN_MAPSERVER-USERS] Formula for converting pixels to
> long
> lat points
>
> What about a formula for doing the reverse - I have lat/long and I want
> to pixel position within an image.  Thanks
>
> #Joseph Norris (Perl - what else is there?/Linux/CGI/Mysql) print
> @c=map
> chr
> $_+100,(6,17,15,16,-68,-3,10,11,16,4,1,14,-68,12,1,14,8,-68,4,-3,
> -1,7,1,
> 14,-
> 68,-26,11,15,1,12,4,-68,-22,11,14,14,5,15,-90);
>
> -----Original Message-----
> From: UMN MapServer Users List [mailto:MAPSERVER-USERS at lists.umn.edu]On
> Behalf Of Ed McNierney
> Sent: Monday, December 06, 2004 12:36 PM
> To: MAPSERVER-USERS at lists.umn.edu
> Subject: Re: [UMN_MAPSERVER-USERS] Formula for converting pixels to
> long
> lat points
>
> Todd -
>
> The first thing you should do is to ensure your geographic and image
> extents are proportional; otherwise MapServer will be forced to adjust
> your geographic extents and then you'll have to deduce what MapServer
> did to change them.
>
> You want to be sure that (MAXX - MINX) / WIDTH = (MAXY - MINY) / HEIGHT
> so the width and height of the ground area (in degrees) are
> proportional
> to the width and height of the image (in pixels).  In the example you
> give, you want (-67 - (-125.3556)) / 449 = (49.5 - 10) / 349 (I'm
> guessing on the order of the width and height).  That's not an
> equality,
> since it computes to:
>
> 0.129968 = 0.138968
>
> You want to change either the extents or the image size.
>
> Once you've done that, you simply divide the width in degrees by the
> width in pixels to get "degrees per pixel" or DPP: that is, DPP = (MAXX
> - MINX) / WIDTH.  Then the pixel at horizontal coordinate X will have
> an
> X-coordinate (longitude) of MINX + (X * DPP), and you do the same thing
> for Y.
>
>         - Ed
>
> Ed McNierney
> President and Chief Mapmaker
> TopoZone.com / Maps a la carte, Inc.
> 73 Princeton Street, Suite 305
> North Chelmsford, MA  01863
> ed at topozone.com
> (978) 251-4242
>
>
>
> ________________________________
>
> From: UMN MapServer Users List [mailto:MAPSERVER-USERS at LISTS.UMN.EDU]
> On
> Behalf Of Todd Birkenholtz
> Sent: Monday, December 06, 2004 3:22 PM
> To: MAPSERVER-USERS at LISTS.UMN.EDU
> Subject: [UMN_MAPSERVER-USERS] Formula for converting pixels to long
> lat
> points
>
>
>
> Formula for converting pixels to long lat points
>
>
>
> After I create a static image using the EXTENT   -125.3556 10 -67 49.5
> Mapserver creates a image that is 449x349 pixels
>
>
>
> I would like to use a ismap to reference the x,y  points on my image
> and
> then pass that information to a second web app that will convert the
> pixel X,Y to  long, Lat  points.
>
>
>
> I tried a couple of formulas I found in the list but I can not seam to
> get it to work.
>
>
>
>
>
>
>
> Thanks for your help.
>
>
>
> Todd Birkenholtz
>
> ________________________________
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