simple tool for conversion

[Joseph Norris]

I would like to thank you for your help -  AT LAST - I have my proof of
concept and it all had to do with the maps that I was using.  Thanks to you
and to all.

#Joseph Norris (Perl - what else is there?/Linux/CGI/Mysql) print @c=map chr
$_+100,(6,17,15,16,-68,-3,10,11,16,4,1,14,-68,12,1,14,8,-68,4,-3,-1,7,1,14,-
68,-26,11,15,1,12,4,-68,-22,11,14,14,5,15,-90);

-----Original Message-----
From: UMN MapServer Users List [mailto:MAPSERVER-USERS at lists.umn.edu]On
Behalf Of Eric Bridger
Sent: Thursday, December 09, 2004 2:04 PM
To: MAPSERVER-USERS at lists.umn.edu
Subject: Re: [UMN_MAPSERVER-USERS] simple tool for conversion

On Thu, 2004-12-09 at 16:17, Joseph Norris wrote:
> Eric,
>
> Thank you for this information.  If I have to switch shapefiles to get
this
> to work - then I am all for it.  So as I understand you,
>
> I have obtained the California state map as you indicated on your link.
> Does this mean that I can build my teacher shape file using the actual
> lat/long that I have and then I would be closer to my new California state
> map knowing about my new teacher shapefile?

Yes. These are zipcode polygons with no projection, in latitude
longitude.

You can use: mapserver-N.N.N/mapscript/perl/examples/shpinfo.pl
-file=zt06_d00  to find the extents and the field names in the DBF.