[OpenLayers-Users] Get Feature Info in pop up working example

[sunny74]

Hi Robert,

Thanks for your reply.

how do u create the following files:

HEADER   ../templates/synlait_query_header.html
  TEMPLATE ../templates/synlait_query_body.html

Pls send the html code for the above and also pls compare your format in
these two files with the actual data of the .shp file as you see in DB.

I have kept both the files blank in the template folder.
Is it absolutely necessary to have these two.

Presently I am having the following errors:

#!/usr/bin/env python """This is a blind proxy that we use to get around
browser restrictions that prevent the Javascript from loading pages not on
the same server as the Javascript. This has several problems: it's less
efficient, it might break some sites, and it's a security risk because
people can use this proxy to browse the web and possibly do bad stuff with
it. It only loads pages via http and https, but it can load any content
type. It supports GET and POST requests.""" import urllib2 import cgi import
sys, os # Designed to prevent Open Proxy type stuff. allowedHosts =
['www.openlayers.org', 'openlayers.org', 'labs.metacarta.com',
'world.freemap.in', 'prototype.openmnnd.org', 'geo.openplans.org',
'sigma.openplans.org', 'www.openstreetmap.org'] method =
os.environ["REQUEST_METHOD"] if method == "POST": qs =
os.environ["QUERY_STRING"] d = cgi.parse_qs(qs) if d.has_key("url"): url =
d["url"][0] else: url = "http://www.openlayers.org" else: fs =
cgi.FieldStorage() url = fs.getvalue('url', "http://www.openlayers.org")
try: host = url.split("/")[2] if allowedHosts and not host in allowedHosts:
print "Status: 502 Bad Gateway" print "Content-Type: text/plain" print print
"This proxy does not allow you to access that location (%s)." % (host,)
print print os.environ elif url.startswith("http://") or
url.startswith("https://"): if method == "POST": length =
int(os.environ["CONTENT_LENGTH"]) headers = {"Content-Type":
os.environ["CONTENT_TYPE"]} body = sys.stdin.read(length) r =
urllib2.Request(url, body, headers) y = urllib2.urlopen(r) else: y =
urllib2.urlopen(url) # print content type header i = y.info() if
i.has_key("Content-Type"): print "Content-Type: %s" % (i["Content-Type"])
else: print "Content-Type: text/plain" print print y.read() y.close() else:
print "Content-Type: text/plain" print print "Illegal request." except
Exception, E: print "Status: 500 Unexpected Error" print "Content-Type:
text/plain" print print "Some unexpected error occurred. Error text was:", E 

Why are these error coming?
How to solve them?

Thanks again. 
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