[postgis-users] TR: add group number to a group by clause

[Olivier Leprêtre]

Hi James,

 

Thanks it helped me (I didn't understood what you would for 'y') but I found this way of doing :

 

select case when lag(o.geom) OVER (PARTITION BY o.geom) = o.geom then '' else 'x ' || o.nbre::text end ,d.code,d.numero,d.nomvoie,d.commune from

(select geom,count(*) as nbre from adress group by geom having count(*) >1) as o,

         lateral (select * from adress order by numero,nomvoie,commune ) as d where st_within(o.geom,d.geom) 

 

in this case, each group begins with 'x times'. I do not add any value in the first column until next change. Not what I was thinking about at the beginning but perhaps easier to understand !

 

Olivier

 

De : postgis-users [mailto:postgis-users-bounces at lists.osgeo.org] De la part de James Keener
Envoyé : jeudi 20 juillet 2017 20:18
À : PostGIS Users Discussion
Objet : Re: [postgis-users] add group number to a group by clause

 

You could try something with a window function. Something like case when lag(x) = x then y else y + 1 end

 

On Thu, Jul 20, 2017 at 1:53 PM, Olivier Leprêtre <o.lepretre at gmail.com> wrote:

Hi,

 

I have sets of points which are piled up by groups. I found how to show the different groups with the query below but I didn't find how to add a group number for each group. I tried with "over partition" but it seems that it's not possible to partition with geom column.

 

Here is the query :

 

select o.nbre,d.code,d.numero,d.nomvoie,d.commune from

(select geom,count(*) as nbre from adress group by geom having count(*) >1) as o,

         lateral (select * from adress) as d where st_within(o.geom,d.geom)

 

it returns the piled points preceded with piled points count.

 

3 pointa (3 piled points)

3 pointf

3 pointg

2 point1 (2 pp)

2 point2

4 pntw   (4 pp)

4 pntx

4 pnty

4 pntz

 

How can I add a group column like this ?

 

1        3 pointa

1        3 pointf

1        3 pointg

2        2 point1

2        2 point2

3        4 pntw

3        4 pntx

3        4 pnty

3        4 pntz

 

 

Thanks for any idea,

 

Olivier

 

 

 

 

 

 

 


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