[Qgis-developer] What's the difference between provider.geometryType() and layer.geometryType()
Victor Olaya
volayaf at gmail.com
Sat Oct 19 10:54:10 PDT 2013
I wasn't aware of that difference that Martin mentions. I guess that,
from the Processing side, the only thing to do is to document clearly
which find of enumeration value is expected, and also how to convert
it in case you have a value corresponding to the other enumeration. I
will try to add that to the Processing documentation
thanks for finding this issue
2013/10/19 Martin Dobias <wonder.sk at gmail.com>:
> Hi Anita
>
> looking into the code... the unintuitive part is that these
> geometryType() methods return values from different enumerations:
> - provider's geometryType() returns value from WKBType enumeration
> - layer's geometryType() returns value from GeometryType enumeration
> (translated from provider's geometryType())
>
> GeometryType has just coarse differentiation (Point, Line, Polygon,
> UnknownGeometry, NoGeometry), while WKBType is more fine grained
> (WKBPoint, WKBPoint2D, WKBMultiPoint, ...)
>
> I totally agree that it is confusing... they should be at least called
> differently (e.g. geometryWkbType vs geometryType).
>
> Regards
> Martin
>
>
> On Sat, Oct 19, 2013 at 9:46 PM, Anita Graser <anitagraser at gmx.at> wrote:
>> Hi Victor,
>>
>> I've been porting one of my scripts to the new Processing. Everything seems
>> fine but I'm confused about one issue:
>> It seems like almost everything can be accessed via the layer now, e.g.
>> crs(), pendingFields(), etc. However, if I try to use layer.geometryType()
>> in the VectorWriter constructor, I get an error. It only works if I do:
>>
>> writer = VectorWriter(output, None, fields, provider.geometryType(),
>> layer.crs() )
>>
>> What's the reason for this unintuitive behavior?
>>
>> Thanks and best wishes,
>> Anita
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