[Qgis-user] Control Layers using Atlas

[Alexandre Neto]

Hi,

I made a few tests and, it works well for vector layer. All you need is the
right coverage layer, a top rule in all layers that you need to controlo.
Like you said, Yhis does not work for raster layer, neither it work for
vector renderers like ppint displacement or heatmap.

Also using legend filter, one can also adapt the maps legend.

Em sex, 14 de ago de 2015 às 12:10, Thomas Colley <
it087 at neath-porttalbot.gov.uk> escreveu:

> Hi Alexandre
>
>
>
> I think the rule based symbology would work but I’m trying to print a
> series of raster layers so unfortunately that’s not an option this time.
>
>
>
> Thanks for your help, I’ll keep looking into it and let you know if I find
> anything.
>
>
>
> Tom
>
>
>
>
>
>
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> *From:* Alexandre Neto [mailto:senhor.neto at gmail.com]
> *Sent:* 14 August 2015 11:59
> *To:* Thomas Colley; qgis-user at lists.osgeo.org
> *Subject:* Re: [Qgis-user] Control Layers using Atlas
>
>
>
> Hello Thomas,
>
> I had that need aswell. If data defined properties were made possible in
> the map composer lock preset option, that would be something direct to do.
>
> Just occured that one might somehow achieve that by transforming each
> layer's symbology into a rule-based symbology, and set a general rule to
> render the feature only if there is a match between a atlas coverage field.
> Dont' know if that would work, but it worth a try.
>
> Let me know if you could do it.
>
> Alexandre Neto
>
>
>
> Em sex, 14 de ago de 2015 às 11:44, Thomas Colley <
> it087 at neath-porttalbot.gov.uk> escreveu:
>
> Hi
>
> Is it possible to use Atlas to print out a number of maps each showing a
> different layer instead of a different area of interest?
>
> I'm thinking the atlas layer would have the same area of interest polygon
> duplicated with an attribute that holds the layer name(s) to be displayed.
>
> I'm sure I have seen this discussed/explained somewhere before but now I
> can't find anything on it, maybe I've just made it up!
>
> Thanks
>
> Tom
>
>
>
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