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<p>Hi Greg,</p>
<p>You can create a virtual column that shows the geometry values in a human readable form. For points it is trivial. Just use $x and $y as expressions, for other geometry types you can write out the WKT string.</p>
<p><a href="https://docs.qgis.org/3.34/en/docs/user_manual/working_with_vector/attribute_table.html#creating-a-virtual-field">https://docs.qgis.org/3.34/en/docs/user_manual/working_with_vector/attribute_table.html#creating-a-virtual-field</a></p>
<p>Hope this helps,</p>
<p>Andreas</p>
<p id="reply-intro">On 2024-09-02 21:37, Greg Troxel via QGIS-User wrote:</p>
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<div class="pre" style="margin: 0; padding: 0; font-family: monospace">When I open the data table, I can't find a way to see the geometry<br />object, in either layer CRS or project CRS.<br /><br />I do see a way to generate a layer which has the attributes as fields:<br /><br /> <a href="https://docs.qgis.org/3.34/en/docs/user_manual/processing_algs/qgis/vectorgeometry.html#add-geometry-attributes" target="_blank" rel="noopener noreferrer">https://docs.qgis.org/3.34/en/docs/user_manual/processing_algs/qgis/vectorgeometry.html#add-geometry-attributes</a><br /><br />But I don't really want to make a layer (which is a copy not a view).<br />I just want the data table to show me the geometry, because it is a<br />column and has a value. (I don't mind that it is read only.)<br /><br />Perhaps I should be using postgis and views to make a layer with extra<br />fields. Any other advice?<br /><br /><br />_______________________________________________<br />QGIS-User mailing list<br /><a href="mailto:QGIS-User@lists.osgeo.org">QGIS-User@lists.osgeo.org</a><br />List info: <a href="https://lists.osgeo.org/mailman/listinfo/qgis-user" target="_blank" rel="noopener noreferrer">https://lists.osgeo.org/mailman/listinfo/qgis-user</a><br />Unsubscribe: <a href="https://lists.osgeo.org/mailman/listinfo/qgis-user" target="_blank" rel="noopener noreferrer">https://lists.osgeo.org/mailman/listinfo/qgis-user</a></div>
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