[GRASS-dev] GRASS Scripts access to channel headers info
Glynn Clements
glynn at gclements.plus.com
Wed Feb 10 20:54:58 EST 2010
António Rocha wrote:
> By the way, I'm having some difficulties in using mapcalc in a python
> scripts.
> I'm doing this
> grass.mapcalc(options['output']=options['raster1']+options['raster2'])
This isn't valid Python syntax.
grass.mapcalc() accepts a template string followed by keyword
arguments for the substitutions, e.g.:
grass.mapcalc("${out} = ${rast1} + ${rast2}",
out = options['output'],
rast1 = options['raster1'],
rast2 = options['raster2'])
Although, I normally copy all of the options[] into separate variables
at the beginning of main(), i.e.:
def main():
output = options['output']
raster1 = options['raster1']
raster2 = options['raster2']
...
grass.mapcalc("${out} = ${rast1} + ${rast2}",
out = output,
rast1 = raster1,
rast2 = raster2)
--
Glynn Clements <glynn at gclements.plus.com>
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