[GRASSLIST:4679] Re: robinson projection
Ian MacMillan
ian_macmillan at umail.ucsb.edu
Thu Oct 28 22:35:27 EDT 2004
I noticed that I had the same problem if I used a Winkel Triple
projection instead of a Robinson projection. It seems like a function
that might be used a lot is one that lays down a latlong grid in any
projection, but maybe that is just me. In any case, as a workaround, I
made a grid in 5.3 with v.mkgrid (unfortunately not available in 5.7)
in my latlong location, projected it into the robinson location with
v.proj, and converted it to a 5.7 vector with v.convert. Worked like a
charm.
-Ian
On Oct 28, 2004, at 6:12 PM, Ian MacMillan wrote:
> Hi all again, I have a weird problem. I am trying to make a world map
> using the robinson projection. I have projected in a raster map of
> the world into this location, and instead of obtaining the nice
> oval-ish shape we are used to, the new raster is a rectangle with
> areas at the edges duplicated. The edges are distorted as they should
> be, but there is no way to determine where the edges of the original
> map lay. I figured this is ok if I could project in a vector box of
> the world (from a latlong location), and just use that as a mask.
> Trouble is that when I project in a vector area with bounding
> coordinates of n=72 s=-72 e=180 w=-180 in latlong space, it comes into
> the Robinson location as a box, not an oval-ish shape. This doesn't
> make any sense to me. Is this a problem with proj.4? Or is it
> impossible to delineate lines of longitude in the Robinson projection
> (measurement units are meters)?
>
> Thanks for any input y'all might have,
> Ian
>
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