[GRASS-user] r.sun2: "Wh" or "kWh"?
nikos.alexandris at felis.uni-freiburg.de
Wed Jun 4 18:24:56 EDT 2008
On Wed, 2008-06-04 at 22:49 +0200, Marco Pasetti wrote:
> Hi Nikos,
> AFAIK r.sun2 calculates the daily global irradiation as [kWh].[m-2].[d-1]
> unfortunately I cannot check it because, at the moment, I don't have GRASS
> installed; but we could simply confirm this by checking the values given by
> just give me an example of returned data from given location, azimuth and
> tilt (and day, obviously), and I'll tell you if that value makes sense in Wh
> or kWh
Hi Marco (and thank you Markus for passing the question to Thomas).
We've been working a while on our maps and the numbers were confusing
when we further tried to produce some EvapoTranspiration maps. We
believe the first result (r.sun2) is in Wh.
Our method step-by-step:
a. generation of daily global_rad(s) in *** Wh ***
for i in `seq 92 302`; do r.sun2 -s --o elevin=srtm3_stel
aspin=aspect_stel slopein=slope_stel alb=0.23 lin=5.2 lat=4275945
horizon=horizon.45 horizonstep=45 glob_rad=global_rad_$i day=$i; done
b. adding all in one
for i in global_rad_*; do r.mapcalc global_daily_avg=global_daily_avg +
$i; echo "...adding map $i"; done
c. getting the average
r.info -r global_daily_avg
### If this would be kWh then we would need to multiply by 3600 in the
next step to get kJ. So we did but the result was way too high than what
we expected. ###
d. converting from *** Wh *** to kJ (and integer to ease off/ speed up
r.mapcalc global_daily_avg_kJ="int(global_daily_avg * 3,6)"
r.info -r global_daily_avg_kJ
2. temperature_int #to get rid some problem with d.rast.leg when using
the floating point temperature map
3. formula #this is based on the formula (Rs/2450)*((0.025*T)+0.08)
r.info -r formula
4. Further processing...
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