[mapguide-users] Specify Shapefile Geometry
Jason Birch
Jason.Birch at nanaimo.ca
Tue Apr 11 16:05:58 EDT 2006
Hi Rod,
Are you sure that "Shape" is the field with the geometry in it? In my
experience, shapefiles that are loaded by a Load Procedure use a
geometry column of "Geometry".
Try echoing out the following:
$featureReader->GetClassDefinition()->GetDefaultGeometryPropertyName();
BTW; Sylvan Lake is cool. My aunt and uncle have a farm near
Bluffton/Rimbey and I've been there for both summers and ice fishing.
Good memories.
Jason
________________________________
From: Rod Buchinski [mailto:rbuchinski at sylvanlake.ca]
Sent: Tuesday, April 11, 2006 12:21
To: users at mapguide.osgeo.org
Subject: [mapguide-users] Specify Shapefile Geometry
Good Day,
For some reason mapguide is unable to understand the geometry of my
shapefile. The shapefile is a polygon with the geometry information
contained in the 'Shape' field. However when I use the 'Shape' field in
the following code I get an error which states: "The specified object
was not found - GetItem line 115".
Here is the code:
$byteReader =
$featureReader->GetGeometry('Shape');
$geometry =
$geometryReaderWriter->Read($byteReader);
$point =
$geometry->GetCentroid();
$x =
$point->GetCoordinate()->GetX();
$y =
$point->GetCoordinate()->GetY();
so what I think should happen here is the GetGeometry function should
look at the 'Shape' field, identify that the shapefile is a polygon,
then get the xy coordinates of the centroid of the polygon which is then
sent to another function which can then zoom to those coordinates. But
I keep getting the error that I mentioned. Could anyone point me in the
right direction?
Rod
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