[Qgis-user] Create a polygon with a specific area size

[Ujaval Gandhi]

Yes, thanks Andrea. The scaling factor is the square root of Y/X.

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Ujaval Gandhi
Spatial Thoughts
www.spatialthoughts.com
[https://mailtrack.io/l/75c7a0eec4fbbbad31e850fd34dcd288da9eb9d3?url=http%3A%2F%2Fwww.spatialthoughts.com&u=8747767&signature=a321f1b8575aaafb]




[data:image/gif;base64,R0lGODlhAQABAIAAAP///wAAACwAAAAAAQABAAACAkQBADs=3D]
On Tue, Aug 27, 2024 at 9:43 PM Andrea Giudiceandrea via QGIS-User
<qgis-user at lists.osgeo.org> wrote:


> > Ujaval Gandhi ujaval at spatialthoughts.com [http://spatialthoughts.com]
> > Tue Aug 27 07:28:22 PDT 2024
> 
> > If you 'Identify' the polygon, it will display the polygon Area in square
> meters
> > under the 'Derived' section. Let's call this X. If your desired area is Y,
> > the scaling factor is Y/X. Use this scaling factor and scale it using the
> > 'Scale' tool in the Advanced Digitizing toolbar.
> 
> Hi all,
> AFAIK the correct scaling factor to use is not Y/X, but the square root
> of Y/X instead.
> 
> Regards.
> 
> Andrea
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